(yz^2+5yz+7)+(2yz^2-yz)=

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Solution for (yz^2+5yz+7)+(2yz^2-yz)= equation:


Simplifying
(yz2 + 5yz + 7) + (2yz2 + -1yz) = 0

Reorder the terms:
(7 + 5yz + yz2) + (2yz2 + -1yz) = 0

Remove parenthesis around (7 + 5yz + yz2)
7 + 5yz + yz2 + (2yz2 + -1yz) = 0

Reorder the terms:
7 + 5yz + yz2 + (-1yz + 2yz2) = 0

Remove parenthesis around (-1yz + 2yz2)
7 + 5yz + yz2 + -1yz + 2yz2 = 0

Reorder the terms:
7 + 5yz + -1yz + yz2 + 2yz2 = 0

Combine like terms: 5yz + -1yz = 4yz
7 + 4yz + yz2 + 2yz2 = 0

Combine like terms: yz2 + 2yz2 = 3yz2
7 + 4yz + 3yz2 = 0

Solving
7 + 4yz + 3yz2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + 4yz + -7 + 3yz2 = 0 + -7

Reorder the terms:
7 + -7 + 4yz + 3yz2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 4yz + 3yz2 = 0 + -7
4yz + 3yz2 = 0 + -7

Combine like terms: 0 + -7 = -7
4yz + 3yz2 = -7

Reorder the terms:
7 + 4yz + 3yz2 = -7 + 7

Combine like terms: -7 + 7 = 0
7 + 4yz + 3yz2 = 0

The solution to this equation could not be determined.

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